125x=(1/25)^4-x

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Solution for 125x=(1/25)^4-x equation: 



125x=(1/25)^4-x

We move all terms to the left:

125x-((1/25)^4-x)=0



Domain of the equation: 25)^4-x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

125x-((+1/25)^4-x)=0

We multiply all the terms by the denominator


125x*25)^4-x)-((+1=0

Wy multiply elements

3125x^2+1=0

a = 3125; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·3125·1
Δ = -12500
Delta is less than zero, so there is no solution for the equation

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